Ratio (Pri5)/ Ratio Sembawang Primary School / Homework (2018) $\mathrm{Jennifer},\mathrm{Yvonne}\mathrm{and}\mathrm{Emeline}\mathrm{altogether}\mathrm{have}\mathrm{some}\mathrm{stickers}.\phantom{\rule{0ex}{0ex}}\mathrm{Jennifer}\mathrm{has}\mathrm{thrice}\mathrm{as}\mathrm{many}\mathrm{stickers}\mathrm{as}\mathrm{Yvonne}\mathrm{and},\phantom{\rule{0ex}{0ex}}\mathrm{twice}\mathrm{as}\mathrm{many}\mathrm{stickers}\mathrm{as}\mathrm{Emeline}.\phantom{\rule{0ex}{0ex}}\mathrm{If}\mathrm{Yvonne}\mathrm{has}92\mathrm{stickers}\mathrm{less}\mathrm{than}\mathrm{Jennifer},\phantom{\rule{0ex}{0ex}}\mathrm{how}\mathrm{many}\mathrm{stickers}\mathrm{do}\mathrm{they}\mathrm{have}\mathrm{in}\mathrm{all}?$
So

$J:Y:E\phantom{\rule{0ex}{0ex}}3:1:1.5\phantom{\rule{0ex}{0ex}}6:2:3\left(x2\right)\phantom{\rule{0ex}{0ex}}6\mathrm{parts}2\mathrm{parts}=92\phantom{\rule{0ex}{0ex}}1\mathrm{part}=23\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Total}=(6+2+3)\mathrm{parts}\phantom{\rule{0ex}{0ex}}=11\times 23\phantom{\rule{0ex}{0ex}}=253\left(\mathrm{ans}\right)\phantom{\rule{0ex}{0ex}}$ 


