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Geometry (Pri-4)

/ Angles Rosyth School / Homework (2018)
square, BGHC is a parallelogram, DFBG and AFEH In the figure below, ABCD is a are straight lines. Given that EHC 65°, find Z FAB. 65° //Н
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August 26, 2018
 
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Aug 26, 2018 09:18 AM
Thank you very much!

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ABD = 45°ABD = BGH = BCH = 45°From triangle HEC:HEC = 180 - 65 - 45 = 70°So BEA = HEC = 70°From triagle ABE:FAB = 180 - 90 - 70 = 20°  (ans)
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August 26, 2018
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