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# Measurement (Pri-6)

/ Circles Stamford Primary School / Homework (2018)
$6. In the figure below, ABDE is a square, EFD is an equilateral triangle and FBCD is a parallelogra\frac{}{}\mathrm{m. Find \left(a\right) LCDF \left(b\right) ZAFE ce}$

June 21, 2018
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Jun 21, 2018 03:21 AM
GUIDE: The key to solving this is to see that length DF = DB because of ED is part of square AND part of equilateral triangle