$\mathrm{answer}774\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{focus}\mathrm{on}\mathrm{After}\mathrm{approach}$

Ans = 24999 $\frac{3}{4}$34

$6+6+1+1=14$

$\mathrm{first},\mathrm{we}\mathrm{see}\mathrm{how}\mathrm{many}\mathrm{boxes}\mathrm{of}12\mathrm{she}\mathrm{can}\mathrm{buy}:\phantom{\rule{0ex}{0ex}}250\xf732=7.8(\mathrm{max}7\mathrm{boxes})\phantom{\rule{0ex}{0ex}}7\times 32=224\phantom{\rule{0ex}{0ex}}250-224=26\phantom{\rule{0ex}{0ex}}26\xf710.9=2.4(\mathrm{max}2\mathrm{boxes})\phantom{\rule{0ex}{0ex}}\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{tarts}=(7\times 12)+(2\times 4)=92\phantom{\rule{0ex}{0ex}}\mathrm{answer}92\phantom{\rule{0ex}{0ex}}$

Hi Hong Chi, try out the search function (*see search bar on the
right) by entering Level: 6, Topic: Ratio & Post Type: Video
Lectures. You will discover that you can also

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5000 ÷ 50 = 100

3.69

- 1.40

__________

2.29

$\mathrm{ans}774$

$\mathrm{answer}220$

$\mathrm{ans}\$120$

INTERESTING SIDE NOTE: in an ideal condition, the ball will bounce
forever... ever closer to 0 cm but never quite reaching it :)

$\mathrm{answer}25\mathrm{days}$

$\mathrm{answer}\$210$

$\mathrm{The}\mathrm{answer}\mathrm{is}13$

$11\mathrm{players}$

$\mathrm{AB}=\mathrm{AC}=L\phantom{\rule{0ex}{0ex}}{L}^{2}+{L}^{2}={15}^{2}\phantom{\rule{0ex}{0ex}}2{L}^{2}=225\phantom{\rule{0ex}{0ex}}{L}^{2}=\frac{225}{2}\phantom{\rule{0ex}{0ex}}\mathrm{Area}=\frac{1}{2}(L\times L)\phantom{\rule{0ex}{0ex}}=\frac{1}{2}{L}^{2}=\frac{1}{2}\times \frac{225}{2}=56.25{\mathrm{cm}}^{2}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}$

$\mathrm{If}\mathrm{you}\mathrm{rotate}\mathrm{the}\mathrm{shaded}\mathrm{triangle},\mathrm{there}\mathrm{will}\mathrm{be}a\mathrm{point}\mathrm{when}\mathrm{all}\mathrm{the}3\mathrm{corners}\phantom{\rule{0ex}{0ex}}\mathrm{of}\mathrm{that}\mathrm{triangle}\mathrm{touches}\mathrm{the}\mathrm{outer}\mathrm{big}\mathrm{triangle}.\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{From}\mathrm{that}\mathrm{we}\mathrm{can}\mathrm{deduce}\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{big}\mathrm{triangle}\mathrm{is}4\mathrm{times}\mathrm{that}\mathrm{of}\mathrm{the}\mathrm{shaded}\mathrm{triangle}.\phantom{\rule{0ex}{0ex}}\mathrm{So}\mathrm{area}\mathrm{of}\mathrm{unshaded}\mathrm{part}\mathrm{is}\frac{3}{4}\phantom{\rule{0ex}{0ex}}\mathrm{Ans}:(3)$

$\mathrm{This}\mathrm{is}a\mathrm{test}\mathrm{answer}28/8/2018,11.20\mathrm{am}.$

$\mathrm{as}\mathrm{dasd}\mathrm{sad}\mathrm{ad}\mathrm{sadasd}\mathrm{as}$

$\mathrm{test}4$

$\mathrm{Muthu}\mathrm{ran}\mathrm{for}=5000\xf7200=25\mathrm{min}\phantom{\rule{0ex}{0ex}}\mathrm{Joe}\mathrm{ran}4250m\mathrm{in}25\mathrm{min}\phantom{\rule{0ex}{0ex}}\mathrm{So}\mathrm{Joe}\mathrm{speed}=4250\xf725=170m/\mathrm{min}\left(\mathrm{ans}\right)\phantom{\rule{0ex}{0ex}}$

$\mathrm{Perimeter}\mathrm{of}\mathrm{shaded}\mathrm{area}=\mathrm{length}\mathrm{of}(\mathrm{outer}\mathrm{big}\mathrm{semicircle}+\mathrm{inner}\mathrm{small}\mathrm{semicircle}+7+7)\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Length}\mathrm{of}\mathrm{big}\mathrm{semicircle}=\frac{1}{2}\left(2\mathrm{\pi r}\right)=\frac{22}{7}\times 21=66\mathrm{cm}\phantom{\rule{0ex}{0ex}}\mathrm{Length}\mathrm{of}\mathrm{big}\mathrm{semicircle}=\frac{1}{2}\left(2\mathrm{\pi r}\right)=\frac{22}{7}\times 14=44\mathrm{cm}\phantom{\rule{0ex}{0ex}}\mathrm{So}\mathrm{Perimeter}\mathrm{of}\mathrm{shaded}\mathrm{area}=66+44+7+7=124\mathrm{cm}\left(\mathrm{ans}\right)\phantom{\rule{0ex}{0ex}}$

11×3.50 = 38.50

Answer (a) = $38.50

38.50 - 1.75 = 36.75

11 + 4 = 15

36.75 ÷15 = 2.45

Price of rice after discount $2.45

Discount = 3.50-2.45 = 1.05

% discount = (1.05÷3.50) ×100 = 30%

Answer (b) = 30%

3×2.50 =7.50

9÷2= 4.50

8+7.50+4.50= 20

50-20 =30

answer $30

Length = y+7

perimeter = y+y+(y+7)+(y+7)

= 4y + 14

answer (4)

18-3 = 15

$\frac{1}{3}$13 × 15 = 5

He ate 5 cookies

$\frac{1}{2}$12 + $\frac{1}{4}$14 + $\frac{1}{8}$18

= $\frac{4}{8}$48 + $\frac{2}{8}$28 + $\frac{1}{8}$18

= $\frac{7}{8}$78

She spent $\frac{7}{8}$78 of her money

1 - $\frac{7}{8}$78 = $\frac{8}{8}$88 - $\frac{7}{8}$78 = $\frac{1}{8}$18

$\frac{1}{8}$18 ×200 = 25

She was left with $25

432-86=346

Xian An has 346 marbles

346 + 432 =778

They have 778 marbles altogether

3U = 42 - 4(3) = 30

1U = 10

Answer 10 kites on day1

78×3=234

80×4=320

320-234=86

answer 86

325- 246 = 79

answer : 79

20×100= 2000

2000-589 = 1411

Rounding off to nearest 10 gives 1410

Answer (4)

answer $797.29

Difference of tarts between 2 cases = 6 + 12 = 18

Therefore no. of neighbours = $\frac{18}{11-9}$1811−9 = 9 (ans)

Total combinations lesser then 75 without condition = 75

Combinations with same numbers: 00, 11, 22, 33, 44, 55, 66 ie 7 combinations

So total combinations with condition = 75 - 7 = 68 (ans)

$\frac{2}{10}$210 + $\frac{3}{5}$35

= $\frac{2}{10}$210 + $\frac{6}{10}$610

= $\frac{8}{10}$810

= $\frac{4}{5}$45

Total households = H

Households with 1 car = $\frac{1}{4}$14 H = $\frac{4}{16}$416 H

Households with 2 cars = $\frac{7}{16}$716 H

Households with 3 cars = $\frac{1}{8}$18 H = $\frac{2}{16}$216 H

Ans (a):

Fraction of household with no cars = 1 - $\frac{4}{16}$416 - $\frac{7}{16}$716 - $\frac{2}{16}$216 = $\frac{3}{16}$316

Ans (b):

Total cars = $\frac{4}{16}$416 H (1) + $\frac{7}{16}$716 H (2) + $\frac{2}{16}$216 H(3) + $\frac{3}{16}$316 H(0) = 1680

$\frac{24}{16}$2416 H = 1680

H = 1120

No of households with 0 cars = $\frac{3}{16}$316 (1120) = 210

A) Area of triangle = $\frac{1}{2}$12 ×10cm×24cm = 120 $cm^2$`c``m`^{2}

B) 2 triangles form a rectangle with length 24cm and breadth 10cm

100÷24 = 4 R4

60÷10 =6

Number of rectangles that can be cut = 4 ×6 =24

Number of triangles that can be cut = 24×2= 48

70

Five hundred and forty three

4/9 x 3/12 = 12/108 = 1/9

Ans: 1/9

Hundreds. 700

450+450=900

All |_____________________| 419 toys

Jayden |__| 50 toys

Jame |____| 1U toys

Eheh |____|____| 2U toys

Jayden + Jame + Eheh = 419

50 + 1U + 2U = 419

3U = 369

U = 369 ÷ 3 = 123

Ans: So Jame have 123 toys

factors of 6 is 2 and 3

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