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me. Class Date: Problem Solving Solve the word problems. were 80singers in asings, The averag e sale singers O singers in a singing competition. The average score given singer was 58.5 points. The average score of the female singers ds o4 points and the average score of the male singers was 56 points. for each Ho w many male singers participated in the competition?

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a week ago
For K, 60 = 270T            T = 4.5h---P travelled for -> 4.5 - 2 = 2.5hFor P,  Speed = 2702.5 = 108 km/h---At 3pm, K & P travelled for 6h & 4h respectivelyDistance apart = 108 ( 4 ) - 60 ( 6 )                         = 72 km 
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Jul-07-2018
GUIDE: draw bar models for boys & girls using same units U, then solve
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a week ago
U = 35 m/minA -> 8U = 8×35 = 280 m/min  (ans, b)B -> 7U = 7×35 = 245 m/min---Speed = DT  ->  D = STFrom B,  D = 280 × 42 = 11760 m---Time taken for B = 11760245 = 48 minsSo B complete at ->  8.00am + 48 mins = 8.48 am  (ans, a)
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Jan-10-2018

Assuming the given equation equals 20, let's solve for 'm".

3 + 3m -1 + 6m = 20

2 + 9m = 20

9m = 18

m = 18 ÷ 9

m = 2

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Jul-22-2018
173 ( n - 5) = 173(n) - 173(5)                    = 173n - 865
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2 weeks ago
From P & L, where U is initial parts,9U - 12 : 8U - 60 ->   6 : 55 ( 9U - 12 ) = 6 ( 8U - 60 )45U - 60 = 48U - 3603U = 300U = 100---Total fruits in the end = (2U + 9U + 8U) - (52 + 12 + 60 )                          = 19 (100) - 124                          = 1776  (ans)
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Feb-04-2018

Total households = H

Households with 1 car = $\frac{1}{4}$14  H =  $\frac{4}{16}$416  H

Households with 2 cars = $\frac{7}{16}$716  H

Households with 3 cars = $\frac{1}{8}$18  H =  $\frac{2}{16}$216  H

Ans (a):

Fraction of household with no cars = 1 - $\frac{4}{16}$416  -  $\frac{7}{16}$716   -  $\frac{2}{16}$216  =  $\frac{3}{16}$316  

Ans (b):

Total cars =  $\frac{4}{16}$416  H (1) +  $\frac{7}{16}$716  H (2) +  $\frac{2}{16}$216  H(3) +  $\frac{3}{16}$316  H(0) = 1680

$\frac{24}{16}$2416  H = 1680

H = 1120

No of households with 0 cars =  $\frac{3}{16}$316  (1120) = 210

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4 days ago
GUIDE: all decimals are fractions of base 10, 100, 1000... depending on how many decimal places. In your question it is 1 decimal place which means 8 parts out of ten or 8/10.
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2 weeks ago
a) Fraction spent on additional pencils = 13 × 45 = 415Cost of 12 highlighters = 4 pencils So total "pencils" bought with 15 of money = 5 + 4 = 9Choose 45 U (parts) since we have 9 & 15---b) Total pencils  = 5U + 12U = 17 pencils (ans)Where U = 1 pencil
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2 weeks ago
Triangle BCG is isosceles, because BG = BCSo BCG =180 - 302  = 75°So GBE = 30° + CBE---CBE = BCG = 75°---a) So GBE = 30° + 75° = 105°---b) GCD = 90° - BCG  = 15°So DGC = 180 - 2(15) = 150°
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3 weeks ago
GUIDE: Firstly determine how many 1/4 m parts he can cut from the 11/12 m string. Then solve.
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4 weeks ago
Hi Sryl, but this is neither P1 math nor Picture Graph :) But you can solve this by forming quadratic equations. Clue: 6 = 2 x 3 & 5 = 2 + 3. Answer & working inside.
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4 weeks ago
Hi Rui Qi, I see you are exploring the app... that's good! You can also take a photo of the question on mobile (go onto Mathemate's mobile site).
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Jul-06-2018
60×0.30 = 18 (total amount of discount)18-0.4 = 17.60 (total amount spent on extra 8 oranges)18 ÷8 = 2.20 ( cost of each orange after discount)cost of each orange after discount = $2.20
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May-30-2018
If you rotate the shaded triangle, there will be a point when all the 3 corners of that triangle touches the outer big triangle.From that we can deduce the area of the big triangle is 4 times that of the shaded triangle.So area of unshaded  part is 34Ans:( 3)
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Apr-25-2018
Perimeter of shaded area = length of (outer big semicircle + inner small semicircle + 7 + 7)Length of big semicircle =12 (2πr) = 227× 21 = 66cmLength of big semicircle =12 (2πr)  = 227×14 = 44cmSo Perimeter of shaded area =66 + 44 + 7 + 7 = 124cm (ans)
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Mar-03-2018

 $\frac{1}{2}$12  $\frac{1}{4}$14  + $\frac{1}{8}$18  

=  $\frac{4}{8}$48  +  $\frac{2}{8}$28  +  $\frac{1}{8}$18  

=  $\frac{7}{8}$78  

She spent  $\frac{7}{8}$78  of her money

 

1 -  $\frac{7}{8}$78  =  $\frac{8}{8}$88  -  $\frac{7}{8}$78  =  $\frac{1}{8}$18  

 $\frac{1}{8}$18  ×200 = 25

She was left with $25 

 

 

 

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Feb-06-2018

  $\frac{2}{10}$210  $\frac{3}{5}$35  

=  $\frac{2}{10}$210  + $\frac{6}{10}$610  

=  $\frac{8}{10}$810  

$\frac{4}{5}$45  

  

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Nov-11-2017

  $\frac{4}{9}$49  ×  $\frac{3}{12}$312   =  $\frac{12}{108}$12108   =  $\frac{1}{9}$19  

 

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Oct-15-2017

All         |_____________________| 419 toys

Jayden  |__| 50 toys

Jame     |____| 1U toys

Eheh     |____|____| 2U toys

Jayden + Jame + Eheh = 419

50 + 1U + 2U = 419

3U = 369

U = 369 ÷ 3 = 123 

Ans: So Jame have 123 toys

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Jul-17-2018
Hello Marcus, what's the question? In addition to typing out a question, you can also upload a photo from your PC. If using mobile or tablet, just take a photo!
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Jul-09-2018
Hi Niyathi, good try:) A better place to post your answer will be by clicking the [Answer] button above, and posting it there. You will also see other user's answers.
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